Organic Chemistry

SOLUTION 7.2a

ee 40 = 0.4 S enantiomer and 0.6 racemic (0.3 S and 0.3 R)
Total S = 0.4 + 0.3 = 0.7 = 70%
Total R = 0.3 = 30% 

ee 68 = 0.68 S enantiomer and 0.32 racemic (0.16 S and 0.16 R)
Total S = 0.68 + 0.16 = 0.84 = 84%
Total R = 0.16 = 16% 

ee 84 = 0.84 S enantiomer and 0.16 racemic (0.08 S and 0.08 R)
Total S = 0.84 + 0.08 = 0.92 = 92%
Total R = 0.08 = 8% 

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