Organic ChemistryMain MenuLecture 1: Introduction to Molecular OrbitalsLecture 10: Intermolecular Forces and Intro to ReactivityLecture 11: Alkenes as Nucleophiles ILectures 12 and 13: Alkenes II & IIILecture 14: Benzenes as Nucleophiles ILecture 15 objectives and skillsLecture 2: Molecular Orbitals in Organic StructuresLecture 3: Molecular Orbitals and ResonanceLecture 4: Molecular Orbitals and AromaticityLecture 5: Nomenclature and IR SpectroscopyLecture 6: Stereochemistry ILecture 7: Stereochemistry IILecture 8: Newman and Fisher ProjectionsLecture 9: Conformations and Cyclohexane RingsJulio Terra2fb22914f73f9e5a767bf7fb83987dca0e153e4a
SOLUTION 21.1a
12020-04-11T13:13:19-07:00Julio Terra2fb22914f73f9e5a767bf7fb83987dca0e153e4a359921plain2020-04-11T13:13:19-07:00Julio Terra2fb22914f73f9e5a767bf7fb83987dca0e153e4aThe second reaction is faster. Substrate is the same, but CH3O- is the better base (anionic vs neutral). In E2 reactions, strength of base affects the activation energy. The first reaction is faster. Substrate is the same, but HO- is the better base (regardless of solvent choice). In E2 reactions, strength of base affects the activation energy.
Which E2 reaction of each pair below would proceed more rapidly? Explain your answer. SOLUTION
Which E1 reaction of each pair below would proceed more rapidly? Explain your answer. SOLUTION
If you made some mistakes or want to practice more, review the concepts that gave you trouble and work on this extra problem. If you're good, move to the problem below ;)
Problem 21.2: Reactivity
Fill in the missing pieces to complete the transformations below. SOLUTION If you made some mistakes or want to practice more, review the concepts that gave you trouble and work on this extra problem. If you're good, move to the next lecture ;)
